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D( x )
x^2+1/5 <= 0
x^2+1/5 <= 0
x^2+1/5 <= 0
1*x^2 <= -1/5
1*x^2 <= -1/5 // : 1
x^2 <= -1/5/1
x^2 <= -1/5
x belongs to the empty set
x in (-oo:+oo)
ln(x^2+1/5) = 0
ln(x^2+1/5) = ln(e^0)
x^2+1/5 = e^0
x^2-e^0+1/5 = 0
1*x^2 = 4/5 // : 1
x^2 = 4/5
x^2 = 4/5 // ^ 1/2
abs(x) = (4/5)^(1/2)
x = (4/5)^(1/2) or x = -(4/5)^(1/2)
x in { (4/5)^(1/2), -(4/5)^(1/2) }
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